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getFileName

getFileName

Description

Retrieves the name portion of a file path, including the extension.

For example, for "c:/temp/take25.c3d", "take25.c3d" will be returned.

Functional area

System

Command syntax

Syntax

getFileName "filePath"

Arguments

NameTypeRequiredComments
filePathstringyesFull path to the file to get the name for. Be sure to use forward slashes instead of back-slashes.

Flags

None

Return value

string

Returns the name portion of a file path, including the extension.

Examples

// Get the name of a file path.
string $name;
string $path = "c:/temp/take25.c3d";
 
// Should print "take25.c3d"
$name = `getFileName $path`;
print $name;

Additional information

Related commands


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